Draw a velocity versus time graph of a stone thrown vertically upwards and then coming downwards after attaining the maximum height.
When a stone is thrown upward, its velocity is at maximum. The velocity begins to drops as the stone attains height. Once the stone attains the maximum height, velocity becomes zero. After that, stone begins to fall down. At this points, velocity beings to rise. Velocity is at its maximum when the stone hits the ground.
The branch of Physics which deals with the motion of objects while taking into consideration the cause of motion is
Slope of a velocity -time graph gives
A car is moving on a straight road with uniform acceleration. The following table gives the speed of the car at various instants of time.
Time $(s)$ | $0$ | $10$ | $20$ | $30$ | $40$ | $50$ |
Speed $\left(m s^{-1}\right)$ | $5$ | $10$ | $15$ | $20$ | $25$ | $30$ |
$(i)$ Draw the speed$-$time graph representing the above set of observations.
$(ii)$ Find the acceleration of the car.
Derive the equation $v^{2}-u^{2}=2 a S$ graphically.
The velocity$-$time graph of a truck is plotted below
$(a)$ Calculate the magnitude of displacement of the truck in $15$ seconds.
$(b)$ During which part of the journey was the truck decelerating ?
$(c)$ Calculate the magnitude of average velocity of the truck.